Pass4Test provide non seulement le produit de qualité, mais aussi le bon service. Si malheureusement vous ne pouvez pas réussir le test, votre argent sera tout rendu. Le service de la mise à jour gratuite est aussi pour vous bien que vous passiez le test Certification.
Le test Certification Oracle 1z0-481 est une chance précieuse à augmenter vos connaissances de technologie informatique dans l'industrie IT. Il attire beaucoup de professionls à participer ce test. Pass4Test peut vous offrir les outils de formation particuliers à propos de test Oracle 1z0-481. Vous réaliserez plus tôt votre rêve avec la Q&A écrite par l'équipe professionnelle de Pass4Test. Pass4Test se contribue à vous donner un coup de main pour réussir le test Oracle 1z0-481.
Pass4Test est aussi un site d'offrir la ressource des connaissances pour le test Certification IT. Selon les Feedbacks venus de gens qui ont untilié les produits de Pass4Test, Pass4Test est un site fiable comme l'outil de se former. Les Q&As offertes par Pass4Test sont bien précises. Les experts de Pass4Test mettent à jour nos documentations de formation de temps de temps.
Pass4Test est un bon site d'offrir la facilité aux candidats de test Oracle 1z1-061. Selon les anciens test, l'outil de formation Oracle 1z1-061 est bien proche de test réel.
Code d'Examen: 1Z0-478
Nom d'Examen: Oracle (Oracle SOA Suite 11g Essentials)
Questions et réponses: 75 Q&As
Code d'Examen: 1z0-481
Nom d'Examen: Oracle (Oracle GoldenGate 11g Certified Implementation Exam Essentials)
Questions et réponses: 79 Q&As
Code d'Examen: 1z1-061
Nom d'Examen: Oracle (Oracle Database 12c: SQL Fundamentals)
Questions et réponses: 75 Q&As
Vous aurez une assurance 100% à réussir le test Oracle 1z0-481 si vous choisissez le produit de Pass4Test. Si malheuresement, vous ne passerez pas le test, votre argent seront tout rendu.
1z1-061 Démo gratuit à télécharger: http://www.pass4test.fr/1z1-061.html
NO.1 Which three tasks can be performed using SQL functions built into Oracle Database?
A. Displaying a date in a nondefault format
B. Finding the number of characters in an expression
C. Substituting a character string in a text expression with a specified string
D. Combining more than two columns or expressions into a single column in the output
Answer: A,B,C
certification Oracle 1z1-061 1z1-061 examen 1z1-061 examen certification 1z1-061
NO.2 Which normal form is a table in if it has no multi-valued attributes and no partial
dependencies?
A. First normal form
B. Second normal form
C. Third normal form
D. Fourth normal form
Answer: B
certification Oracle certification 1z1-061 certification 1z1-061 1z1-061 examen
NO.3 Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It executes successfully and displays rows in the descending order of PROMO_CATEGORY .
B. It produces an error because positional notation cannot be used in the order by clause with set
operators.
C. It executes successfully but ignores the order by clause because it is not located at the end of the
compound statement.
D. It produces an error because the order by clause should appear only at the end of a compound
query-that is, with the last select statement.
Answer: D
certification Oracle certification 1z1-061 certification 1z1-061 certification 1z1-061
NO.4 View the Exhibit and examine the structure of the product, component, and PDT_COMP
tables.
In product table, PDTNO is the primary key.
In component table, COMPNO is the primary key.
In PDT_COMP table, <PDTNO, COMPNO) is the primary key, PDTNO is the foreign key referencing
PDTNO in product table and COMPNO is the foreign key referencing the COMPNO in component
table.
You want to generate a report listing the product names and their corresponding component names,
if the component names and product names exist.
Evaluate the following query:
SQL>SELECT pdtno, pdtname, compno, compname
FROM product _____________ pdt_comp
USING (pdtno) ____________ component USING (compno)
WHERE compname IS NOT NULL;
Which combination of joins used in the blanks in the above query gives the correct output?
A. JOIN; JOIN
B. FULL OUTER JOIN; FULL OUTER JOIN
C. RIGHT OUTER JOIN; LEFT OUTER JOIN
D. LEFT OUTER JOIN; RIGHT OUTER JOIN
Answer: C
certification Oracle 1z1-061 examen certification 1z1-061 1z1-061 1z1-061 examen certification 1z1-061
NO.5 View the Exhibit for the structure of the student and faculty tables.
You need to display the faculty name followed by the number of students handled by the faculty at
the base location.
Examine the following two SQL statements:
Which statement is true regarding the outcome?
A. Only statement 1 executes successfully and gives the required result.
B. Only statement 2 executes successfully and gives the required result.
C. Both statements 1 and 2 execute successfully and give different results.
D. Both statements 1 and 2 execute successfully and give the same required result.
Answer: D
Oracle examen certification 1z1-061 certification 1z1-061 certification 1z1-061 certification 1z1-061
NO.6 Examine the structure proposed for the transactions table:
Which two statements are true regarding the creation and storage of data in the above table
structure?
A. The CUST_STATUS column would give an error.
B. The TRANS_VALIDITY column would give an error.
C. The CUST_STATUS column would store exactly one character.
D. The CUST_CREDIT_LIMIT column would not be able to store decimal values.
E. The TRANS_VALIDITY column would have a maximum size of one character.
F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes,
seconds, and fractions of seconds
Answer: B,C
Oracle 1z1-061 examen 1z1-061 examen certification 1z1-061 1z1-061 examen
Explanation:
VARCHAR2(size)Variable-length character data (A maximum size must be specified:
minimum size is 1; maximum size is 4, 000.)
CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size
is 1; maximum size is 2, 000.)
NUMBER [(p, s)] Number having precision p and scale s (Precision is the total number of
decimal digits and scale is the number of digits to the right of the decimal point; precision
can range from 1 to 38, and scale can range from -84 to 127.)
DATE Date and time values to the nearest second between January 1, 4712 B.C., and
December 31, 9999 A.D.
NO.7 Examine the types and examples of relationships that follow:
1.One-to-one a) Teacher to students
2.One-to-many b) Employees to Manager
3.Many-to-one c) Person to SSN
4.Many-to-many d) Customers to products
Which option indicates the correctly matched relationships?
A. 1-a, 2-b, 3-c, and 4-d
B. 1-c, 2-d, 3-a, and 4-b
C. 1-c, 2-a, 3-b, and 4-d
D. 1-d, 2-b, 3-a, and 4-c
Answer: C
certification Oracle certification 1z1-061 1z1-061 1z1-061 certification 1z1-061
NO.8 View the Exhibit and evaluate the structure and data in the CUST_STATUS table.
You issue the following SQL statement:
Which statement is true regarding the execution of the above query?
A. It produces an error because the AMT_SPENT column contains a null value.
B. It displays a bonus of 1000 for all customers whose AMT_SPENT is less than CREDIT_LIMIT.
C. It displays a bonus of 1000 for all customers whose AMT_SPENT equals CREDIT_LIMIT, or
AMT_SPENT is null.
D. It produces an error because the TO_NUMBER function must be used to convert the result of the
NULLIF function before it can be used by the NVL2 function.
Answer: C
Oracle examen certification 1z1-061 certification 1z1-061 1z1-061 examen 1z1-061 examen
Explanation:
The NULLIF Function The NULLIF function tests two terms for equality. If they are equal the function
returns a null, else it returns the first of the two terms tested. The NULLIF function takes two
mandatory parameters of any data type. The syntax is NULLIF(ifunequal, comparison_term), where
the parameters ifunequal and comparison_term are compared. If they are identical, then NULL is
returned. If they differ, the ifunequal parameter is returned.
没有评论:
发表评论